x^2+5x-14=(x+7)(x-5)

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Solution for x^2+5x-14=(x+7)(x-5) equation: 



x^2+5x-14=(x+7)(x-5)

We move all terms to the left:

x^2+5x-14-((x+7)(x-5))=0

We multiply parentheses ..

x^2-((+x^2-5x+7x-35))+5x-14=0



We calculate terms in parentheses: -((+x^2-5x+7x-35)), so:

(+x^2-5x+7x-35)

We get rid of parentheses

x^2-5x+7x-35

We add all the numbers together, and all the variables

x^2+2x-35

Back to the equation:

-(x^2+2x-35)



We add all the numbers together, and all the variables

x^2+5x-(x^2+2x-35)-14=0

We get rid of parentheses

x^2-x^2+5x-2x+35-14=0

We add all the numbers together, and all the variables

3x+21=0

We move all terms containing x to the left, all other terms to the right

3x=-21

x=-21/3

x=-7

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